The pressure of 0.540 mol of an ideal gas at 35.5 L and 223K is 0.278atm.
How to calculate pressure?
The pressure of an ideal gas can be calculated by using the ideal gas law equation as follows:
PV = nRT
Where;
- P = pressure
- V = volume
- n = no of moles
- R = gas law constant
- T = temperature
According to this question, 0.540 moles of an ideal gas contains a volume of 35.5 L and a temperature of 223K. The pressure can be calculated as follows:
P × 35.5 = 0.540 × 0.0821 × 223
35.5P = 9.886
P = 0.278atm
Therefore, the pressure of 0.540 mol of an ideal gas at 35.5 L and 223K is 0.278atm.
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