Respuesta :

Considering the Gay Lussac's law,the pressure at 57°C would be 770 Torr.

Gay Lussac's law

Gay Lussac's law establishes the relationship between the temperature and pressure of a gas when the volume is constant.

This law says that the pressure is directly proportional to the temperature of the gas: if the temperature increases, the pressure of the gas increases while if the temperature of the gas decreases, the pressure decreases.

Mathematically, Gay Lussac's law states that the ratio of pressure to temperature is constant:

P÷T= k

If you have an initial state of 1 and a final state of 2, then:

P1÷T1= P2÷T2

Pressure al 57°C

In this case, you know:

  • P1= 812 Torr
  • T1= 75°C= 348 K
  • P2= ?
  • T2= 57°C= 330 K

Replacing in Gay Lussac's law:

812 Torr÷ 348 K= P2÷ 330 K

Solving:

(812 Torr÷ 348 K)× 330 K= P2

770 Torr= P2

Finally, the pressure at 57°C would be 770 Torr.

Learn more about Gay Lussac's law:

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