The number of mole of CaCO₃ in antacid tablet containing 0.512 g of CaCO₃ is 5.12×10⁻³ mole
Description of mole
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
How to determine the mole of CaCO₃
From the question given above, the following data were obtained:
- Mass of CaCO₃ = 0.512 g
- Molar mass of CaCO₃ = 40 + 12 + (3 × 16) = 40 + 12 + 48 = 100 g/mol
- Mole of CaCO₃ =?
The number of mole in 0.512 g of CaCO₃ can be obtained as follow:
Mole = mass / molar mass
Mole of CaCO₃ = 0.512 / 100
Mole of CaCO₃ = 5.12×10⁻³ mole
Thus, 5.12×10⁻³ mole of CaCO₃ is present in the antacid tablet
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