The dimensions of the rectangle are 43inches and 20inches if the perimeter of the rectangle is 126 inches.
Leth the width of the revtangle be x.
According to the given question.
The perimeter of the rectangle is 126 inches.
The length of the rectangle is three more than double the width.
⇒ Length of the rectangle = 3 + 2x
Now, according to the given conditions we can say that
Perimeter of the rectangle = 2( length + width)
⇒ 126 = 2(3 + 2x + x)
⇒ 126 = 2(3 + 3x)
⇒ 63 = 3 + 3x
⇒ 63 - 3 = 3x
⇒ 60 = 3x
⇒ x = 20 inches
Therefore, the length of the rectangle = 3 + 2(20) = 3 + 40 = 43
Hence, the dimensions of the rectangle are 43inches and 20inches if the perimeter of the rectangle is 126 inches.
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