Question

Tanner is going to play at an arcade. There is a $4.50 admission fee, and each game costs $0.75 to play. If Tanner only brought $20.00 to spend, what is the maximum number of games that he can afford to play?​

Answer 1

Answer:

$12 > x$

Step-by-step explanation:

$20 > .75x + 4$

Is the equation you need to set up.

Then you want to subtract four from both sides ehich ends up giving you

$16 > .75x$

Then divide 16 by 4 (this gives you a fourth) you get four

Then multiple 4 by 3 to get .75 of 16 which is 12

Hope this helps!

If yoy have any other questions feel free to ask!

Answer 2

Answer:

Tanner can play 20 games in the arcade and will have 50 cents left over.

Step-by-step explanation:

20 = 4.50 + 0.75x

Subtract 4.5 from both sides.

15.5 = 0.75x

Plug in numbers for x until it is equal more that 15.5

x = 20

0.75(20) = 15

0.75(21) = 15.75 < too much