Question

please help me answer this with solution​

Answer 1

Answer:

Question 1:

${ \tt{f(x) = {x}^{2} - 10x + 25}}$

when f(x) is f(10), we substitute for x as 10; x = 10

${ \tt{f(10) = {10}^{2} - 10(10) + 25 }} \\ { \tt{f(10) = 100 - 100 + 25}} \\ { \boxed{ \tt{ \: f(10) = 25 \: }}}$

Question 2:

${ \tt{f(x) = \frac{2 {x}^{3} - 7 }{10} }}$

when f(x) is f(-1), we substitute for x as -1; x = -1

${ \tt{f( - 1) = \frac{2 {( - 1)}^{3} - 7 }{10} }} \\ \\ { \tt{f( - 1) = \frac{ - 2 - 7}{10} }} \\ \\ { \boxed{ \tt{ \: f( - 1) = - \frac{9}{10} \: }}}$