Using Venn sets, the cardinalities are given as follows:
a) n(A U B) = 15.
b) n(A' U C) = 16.
c) n(A ∩ B)' = 10.
What are Venn probability?
Venn amounts relates the cardinality of sets that intersect with each other.
For this problem, the sets are the ones given in this problem, A, B and C, while U is the universal set.
For this problem, the cardinalities are given as follows:
- n(A ∩ B) = n(A ∩ C) = n(B ∩ C) = 9.
Hence:
- 6 elements belong to all the sets.
- 9 - 6 = 3 belong to these intersections but not the remaining set: A and B, A and C, B and C.
- 15 belong to the union of all of them, hence 4 belong to none.
- 15 - (6 + 3 x 3) = 0 belong to only one set.
Hence:
- n(A U B) = 15, as from the final bullet point, there are no elements that belong to only set C.
- For item b, 6(all) + 3(only A and C) + 3 (only B and C) = 12 elements belong to C, and 4 do not belong to A(the 3 to only B and C is already counted), hence: n(A' U C) = 16, as 12 + 4 = 16.
- For item c, n(A ∩ B) = 9, hence n(A ∩ B)' = n(U) - n(A ∩ B) = 19 - 9 = 10.
More can be learned about Venn sets at https://brainly.com/question/28318748
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