Answer:
(1/3)log(5) +(4/3)log(x) +log(y)
Step-by-step explanation:
You want the expanded form of the expression log(∛5·x^4·y^3).
Rules of logarithms
The applicable rules of logarithms are ...
log(ab) = log(a) + log(b)
log(a^b) = b·log(a)
In addition to these, you need to know that a root is a fractional power: the cube root is the 1/3 power. Of course, the rules of powers tell you ...
(a^b)^c = a^(bc)
Application
You can express the root as a fractional power before or after taking logs. Either way, you get the same result.
Before
[tex]\log\left(\sqrt[3]{5\cdot x^4y^3}\right)=\log\left(5^{\frac{1}{3}}\cdot x^{\frac{4}{3}}y^{\frac{3}{3}}\right)=\boxed{\dfrac{1}{3}\log(5)+\dfrac{4}{3}\log(x)+\log(y)}[/tex]
After
[tex]\log\left(\sqrt[3]{5\cdot x^4y^3}\right)=\dfrac{1}{3}\log\left(5}\cdot x^{4}y^{3}}\right)=\dfrac{1}{3}\left(\log(5)+4\log(x)+3\log(y)\right)\\\\=\boxed{\dfrac{1}{3}\log(5)+\dfrac{4}{3}\log(x)+\log(y)}[/tex]
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Additional comment
Working a more complex problem is like working a simple problem, except it has more parts and may require the use of the rules more times. It may be tedious to keep track of all the parts, but it is not difficult.
