Question

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Homework Progress
24 / 63 Marks
a) Work out the value of (15)*× (√3)?
x
b) Work out the value of (19) × (√30) ?
x
1 14
豐
54%

Answer 1

Answer:

(a)  15

(b)  270

Step-by-step explanation:

Part (a)

Given expression:

$\left(\sqrt{5}\right)^2 \times \left(\sqrt{3}\right)^2$

$\textsf{Apply the exponent rule}:\quad \left(\sqrt[n]{a}\right)^n=a,\quad \textsf{ n is odd or a \geq 0 }$

$\implies 5 \times 3$

Multiply the numbers:

$\implies 15$

Part (b)

Given expression:

$\left(\sqrt[3]{9} \right)^3 \times \left(\sqrt{30}\right)^2$

$\textsf{Apply the exponent rule}:\quad \left(\sqrt[n]{a}\right)^n=a,\quad \textsf{ n is odd or a \geq 0 }$

$\implies 9 \times 30$

Multiply the numbers:

$\implies 270$

Answer 2

Now we have to,

→ work out the value for the following.

We know that,

→ square ( ²) and square root (√) gets cancelled each other.

→ cube ( ³) and cube root (³√) gets cancelled each other.

a) (√5)² × (√3)² = ?

→ (√5)² × (√3)²

→ 5 × 3 = 15

Thus, the answer is 15.

b) (³√9)³ × (√30)² = ?

→ (³√9)³ × (√30)²

→ 9 × 30 = 270

Thus, the answer is 270.