Question

If a 1.5 L saucepan is heated from 22 degrees celsius to 100 degrees celsius, by what percentage will any gas in the pan increase in volume?

Answer 1

Explanation:

$\frac{p1v1}{n1t1} = \frac{p2v2}{n2t2} (ideal \: gas \: equation) \\ \frac{v1}{t1} = \frac{v2}{t2} \\ convert \: degrees \: to \: kelvin \: \\ \frac{1.5l}{297k} = \frac{v2}{373k} \\ v2 = 1.88l \\ it \: increased \: by \: 80\%$