The area of triangle HIJ is 7 square units.
Given that, the vertices of triangle HIJ are H(-9,-8), I(-5,-5), and J(-7,-3) respectively. By using the vertices of triangle HIJ we have to evaluate its area in square units. So, let's procced to solve the question.
Area of ΔHIJ = 1/2|x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)|
So, x₁ = -9, x₂ = -5, x₃ = -7 and y₁ = -8, y₂ = -5, y₃ = -3
Put all the listed values in the formula of area of triangle HIJ.
By using the above formula, we get
=1/2|-9(-5+3)+(-5)(-3+8)+(-7)(-8-(-5))|
=1/2|-9(-2)-5(5)+(-7)(-3)|
=1/2|18-25+21|
=1/2|14|
= 1/2 x 14
= 7
Therefore, the area of triangle HIJ is 7 square units.
Learn more in depth about various points of area of triangle by using vertices at https://brainly.com/question/13938833
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