Respuesta :

The Hailey's comet aphelion distance from the sun is 36 A. U.

The Hailey's comet perihelion distance = 0.6 amu

The Hailey's comet orbital period = 76 years

According to Kepler's law,

The time duration is T.

T = 76 years.

The semi-major axis is a.

The semi-major axis of Hailey's comet is,

[tex]T ^{2} =a ^{3} [/tex]

[tex]a = \sqrt[3]{(T) ^{2} }[/tex]

[tex]a = \sqrt[3]{(76) ^{2} }[/tex]

= 18 A. U

The semi-major axis of Hailey's comet is 18 A. U.

The Hailey's comet aphelion distance from the sun is,

= 2 × a

= 2 × 18

= 36 A. U

Therefore, Hailey's comet aphelion distance from the sun is 36 Astronomical Units.

To know more about aphelion distance, refer to the below link:

https://brainly.com/question/18802364

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