The Hailey's comet aphelion distance from the sun is 36 A. U.
The Hailey's comet perihelion distance = 0.6 amu
The Hailey's comet orbital period = 76 years
According to Kepler's law,
The time duration is T.
T = 76 years.
The semi-major axis is a.
The semi-major axis of Hailey's comet is,
[tex]T ^{2} =a ^{3} [/tex]
[tex]a = \sqrt[3]{(T) ^{2} }[/tex]
[tex]a = \sqrt[3]{(76) ^{2} }[/tex]
= 18 A. U
The semi-major axis of Hailey's comet is 18 A. U.
The Hailey's comet aphelion distance from the sun is,
= 2 × a
= 2 × 18
= 36 A. U
Therefore, Hailey's comet aphelion distance from the sun is 36 Astronomical Units.
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