Question

Two consecutive positive integers such that the square of the second integer added to 4 times the first is equal to 41

Answer 1

Answer:

4 and 5

Step-by-step explanation:

We need 2 positive numbers that are right beside each other, like 1 and 2. When the problem is translates into number format we get:

y^2+4x=41

x = 1st # and y = 2nd #

so if we do 4 (x) and 5 (y)

5^2+4(4)=41

the statement is true.