Question

What is the slope of a line that is perpendicular to a line whose equation is −6y=2x+7?
30 points and brainliest!

Answer 1

Answer:

6/2

Step-by-step explanation:

I AM TOO LAZY TO EXPLAIN IT STEP BY STEP -_-

Answer 2

Answer:

The perpendicular slope is 3.

Explanation:

$\sf slope\:intercept\:form :y = mx + b$

where:

• m = slope
• b = y-intercept

Given equation:

• $-6y=2x+7$

divide both sides by -6

• $\dfrac{-6y}{-6} =\dfrac{2x+7}{-6}$

simplify

• $y=\dfrac{2x}{-6} +\dfrac{7}{-6}$

when simplified more:

• $y=-\dfrac{1}{3}x -\dfrac{7}{6}$

Here the slope is -1/3

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$\sf m_1 \times m_2 = -1$

where:

• m1 = parallel slope
• m2 = perpendicular slope

Find perpendicular slope:

$\sf -\dfrac{1}{3} \times m_2 = -1$

$\sf m_2 = 3$