The length of A'B' is √5 units.
The formula to find the distance between the two points is usually given by
d=√((x2 – x1)² + (y2 – y1)²).
Given :
Quadrilateral ABCD is dilated at the center (0,0) with a scale factor of 1/2 to form quadrilateral A'B'C'D'.
Points - A(0,4), B(4,2), C(4,-4), and D(-2,-2).
So, the points of the quadrilateral ABCD becomes:
So, length of A'B'
AB = √(4-0) ² +(2 -4)²
AB = √16 + 4
AB = √20
AB = 2√5
A'B' = 1/2 AB
A'B' = √5
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