Which element, Oxygen (O) or Fluorine (F), has a smaller atomic radius?

O, because the attraction between protons and valence electrons is weaker.
F, because the attraction between protons and valence electrons is stronger.
F, because the attraction between protons and valence electrons is weaker.
O, because the attraction between protons and valence electrons is stronger.

Respuesta :

Fluorine has a smaller ionic radius than oxygen, because the attraction between protons and valence electrons is stronger; option B

What is ionic radius?

Ionic radius is the radius of an ion of an element given by the distance from the nucleus up to where the nucleus has an influence on the ion's electron cloud.

The ionic radius of ions of elements depends on;

  • the nuclear charge, electron shielding,
  • the number of electron shells as well as
  • the number of electrons in the outermost shell of of an ion of an element.

The greater the nuclear charge, the smaller the ionic radius.

The greater the electron shielding effect, the greater the ionic radius.

For non-metallic  ions just as in metallic ions, the ionic radius decreases from left to right across the period table as a result of the increase in the nuclear charge of the ions.

Also, the ionic radius of nonmetals increase on going down the same group in the periodic table due to to increase in electron shielding as well as addition of an extra electron shell.

Therefore, the ionic radius of fluorine will be smaller than that of oxygen because of a greater nuclear charge.

Learn more about ionic radius at: https://brainly.com/question/2114639

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