Which element, Oxygen (O) or Fluorine (F), has a smaller atomic radius?

O, because the attraction between protons and valence electrons is weaker.
F, because the attraction between protons and valence electrons is stronger.
F, because the attraction between protons and valence electrons is weaker.
O, because the attraction between protons and valence electrons is stronger.

Respuesta :

Fluorine has a smaller ionic radius than oxygen, because the attraction between protons and valence electrons is stronger; option B

What is ionic radius?

Ionic radius is the radius of an ion of an element.

The ionic radius of ions of elements depends on the nuclear charge as well as the number of electrons in the outermost shell of of an ion of an element.

The nuclear charge is the charge on the nucleus as a result of the positively-charged proton present in the nucleus. The proton exerts an attractive force on the electrons, thus reducing the size of the ion if nuclear charge increases.

The ionic radius of metallic ions decrease from left to right across the period table as a result of the increase in the nuclear charge of the ions.

However, the ionic radius of metals increase on going down a group in the periodic table.

Similarly, the ionic radius of non-metallic ions decrease from left to right across the period table as a result of the increase in the nuclear charge of the ions.

The ionic radius of non-metals also increase on going down a group i the periodic table.

Therefore, the ionic radius of oxygen will be greater than that of fluorine because of a smaller nuclear charge.

Learn more about ionic radius at: https://brainly.com/question/6965246

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