The correct answer is 19.7 m/s.
Range is the height of the projectile when it reaches a vertical velocity of zero; after that, gravity will take over and quicken the object's descent. The projectile range, which is determined by the object's initial velocity, is the horizontal displacement of the object projected.
Only when one force is applied at the start of the trajectory does projectile motion occur; thereafter, gravity is the only resistance. A projectile launched under specified beginning circumstances will have a range in physics. Assuming a flat Earth with a consistent gravity field and no air resistance may make it more predictable.
Range R = 38.7 m
Acceleration due to gravity g =9.8 m/s
Launch angle θ = 51
Range of the projectile is given by
R = u^2 Sin2θ / g
u^2 = gR/ Sin 2θ
u = √gR/ Sin 2θ
u = √ 9.8 × 38.7 / Sin ( 2 × 51)
u = 19.7 m/s.
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