Im very confused help
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The values of x not in the domain of g are -4 and 1
The domain of a function is the value of the independent variable for which a function exist
Given the function below;
g(x) = x²+13x+42/x²+3x-4
The function does not exist if the denominator is zero.
x²+3x-4 = 0
Factorize
x²+4x-x-4 = 0
x(x+4)-1(x+4) = 0
x = -4 and 1
Hence the values of x not in the domain of g are -4 and 1
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