Evaluate:
Σ015 (3)
n-1
?
![Evaluate Σ015 3 n1 class=](https://us-static.z-dn.net/files/d20/4fd21e3f4c76308eb44c7035b5ce2ea9.png)
The sum of the given geometric progression to the nearest hundredth is 7.50
The given nth term is an explicit formula for a geometric sequence. The formula for calculating the sum of the given expression is;
Sum = a(1-r^n)/1-r
where
r is the common ratio. = 1/2
n is the number of terms = 10
a is the first term = 5
Substitute to have:
Sum = 5(1-(1/3)^10)/1-1/3
Sum = 5(1-1/59049)/2/3
Sum = (5 - 5/59049) * 3/2
sum = 7.50
Hence the sum of the given geometric progression to the nearest hundredth is 7.50
Learn more on sum of geometric sequence here: https://brainly.com/question/24643676
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