Question

A large spoon is used for serving soup. The part of the spoon that holds the soup is in the shape of a hemisphere (half of a sphere) with
diameter 4 inches. Which is closest to the amount of soup the spoon can hold? (Use π =
3.14)

Answer 1

Answer:  about 16.75 cubic inches

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Explanation:

d = 4 is the diameter

r = d/2 = 4/2 = 2 is the radius

Let's calculate the volume of a full sphere of radius r = 2

$V = \frac{4}{3}\pi*r^3\\\\V \approx \frac{4}{3}*3.14*2^3\\\\V \approx 33.4933333$

The result is approximate since 4/3 doesn't produce a nice decimal value (it produces 1.333 with the 3s repeating); also because pi = 3.14 is approximate.

The result 33.4933333 represents a full sphere volume, but we want half a sphere (aka hemisphere)

We'll divide it in half to get (33.4933333)/2 = 16.74666665 which rounds to about 16.75 cubic inches

Round each value according to the instructions your teacher provides.