Respuesta :
The length and width of a 326 perimeter rectangular playing field are 110.33 and 52.67 yards, respectively.
Let us assign variables for the length and width of the rectangular playing field.
Let: length = l, width = w and perimeter = P
The perimeter of the rectangular playing field is said to be 326 yards. It is calculated by determining the sum of all the sides, which is 2l +2w.
P= 326 yards = 2l + 2w
However, we cannot calculate the measurement of length and width without having two equations. The second equation is based on the relationship between length and width. As stated in the problem, the length is five yards longer (+5 yards) than two times or double the width (2w).
Relationship between length and width: l = 5 + 2w
The measurement of length in terms of width can be substituted into the calculation of perimeter to solve for the value of width.
326 = [2*(5+2w)]+2w
326 = 10 + 4w +2w
326 = 10 + 6w
326 - 10 = 6w
w = 316/6 or 52.67 yards
Then, we can substitute the value of width to solve for the length of the field.
l= 5 + 2(316/6)
l= 331/3 or 110.33 yards
For more information regarding equivalent equations, please refer to the link https://brainly.com/question/2972832.
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