Answer:
[tex]y=\frac{2}{3}x+\frac{4}{3}[/tex]
Step-by-step explanation:
The equation of a line in point-slope form is given by [tex]y-y_1= m(x-x_1)[/tex]. Here, m is the slope while [tex](x_1, y_1)[/tex] is a coordinate on the line.
Given: point (1, 2) and slope= [tex]\frac{2}{3}[/tex]
Upon substitution:
[tex]y-2= \frac{2}{3}(x-1)[/tex]
We now have the equation of the line in the point-slope form.
In the slope-intercept form (y= mx +c), the term y is on the left-hand side of the equation while the rest are on the right of the equation. Ensure that the coefficient of y is 1.
Expand:
[tex]y-2=\frac{2}{3}x-\frac{2}{3}[/tex]
Adding 2 to both sides:
[tex]y= \frac{2}{3}x -\frac{2}{3}+2[/tex]
[tex]\bf{y=\frac{2}{3}x +\frac{4}{3} }[/tex]
To learn more about point-slope form of a line, do check out: https://brainly.com/question/18894159