Question

Wes stands on the roof of a building, leans over the edge, and drops a rock. Lindsay its 1.35 s after Wes releases his
rock and throws her own rock straight down at 27.0 m/s. Both rocks hit the ground simultaneously.
1) Calculate the common height from which the rocks were released. Ignore the effects of air resistance. (Express your
answer to three significant figures.)

Answer 1

19.56m is the common height from which the rocks were released.

Formula used for calculating the height(s) is

s = ut + 1/2gt²

where

s = Common height from which the rocks were released

u = Initial velocity

g = acceleration

t = time period taken

For Wes

Initial velocity(u) = 0

So, s = 1/2gt² .... (1)

For Lindsay

Initial velocity = 27m/s

Time (t) = t - 1.35

So, s = 27(t - 1.35) + 1/2g(t - 1.35)² ..... (2)

From equation (1) and (2)

1/2gt² = 27(t-1.35) + 1/2g(t - 1.35)²

On solving we get

t = 1.998 seconds

Now By putting the calculated value of (t) in equation (1)

s = 1/2 × 9.8 × (1.998)²

s = 19.56 m

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