The distance between the two given points in simplest form is
5. [tex]\text { Distance }=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]
The distance between two points with coordinates
(-3,6) and (-3,-3) is:
HC =9.00 units
(results are in decimal form, rounded to the nearest 100th)
6. [tex]\text { Distance }=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]
The distance between two points with coordinates
(9,-2) and (10,-1) is:
EG =1.41 units
(results are in decimal form, rounded to the nearest 100th)
In this question, we are given two points and we need to find the distance between them in radical form. Therefore, we need to find the distance keeping the square root sign. For this we will generally use the distance formula. The distance between two points [tex]$ \left( {{x}_{1}},{{y}_{1}} \right)\text{ and }\left( {{x}_{2}},{{y}_{2}} \right) $[/tex] is given by the formula, [tex]$ d=\sqrt{{{\left( {{x}_{2}}-{{x}_{1}} \right)}^{2}}+{{\left( {{y}_{2}}-{{y}_{1}} \right)}^{2}}} $[/tex] . We will solve the squares and add them but we will not solve the square root so that it remains in radical form.
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