Respuesta :

Answer:

59.8 m/s

Explanation:

vf = vo + at

   = 50 m/s + 9.81 m/s^2  (1 s) = 59.8 m/s

At one instant an object in free fall is moving downward at 50 m/s. one second later its speed would be 59.81 meters/second because under the free fall motion the only acting force is the gravitational force.

What are the three equations of motion?

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

As given in the problem at one instant an object in free fall is moving downward at 50 m/s and we have to find out the speed after 1 second,

By using the first equation of motion,

v = u + at

v = 50 + 9.81 ×1

v = 59.81 meters/second

Thus, the speed of the falling stone after one second would be 59.81 meters/second

Learn more about equations of motion from here

brainly.com/question/5955789

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