Question

Find the intersection point using substitution or elimination. 2p - 6j = -8 4p + 12j = 8

Answer 1

Point of intersection using substitution (p, j) is (-1, 1).

Given

2p - 6j = -8----------(1)

4p + 12j = 8---------(2)

From equation 1, We can write

2p = -8 + 6j

p = (-8 + 6j)/2

p = -4 + 3j

By using substitution method, substitute p = -4 + 3j in equation 2

4p + 12j = 8

⇒ 4(-4 + 3j) + 12j =8

⇒ 4 × (-4) + 4 × 3j + 12j = 8

⇒ -16 + 12j +12j = 8

⇒ 24j = 8 +16

⇒ 24j = 24

⇒ j = 24/24

⇒ j = 1

then p = -4 +3j

p = -4 + 3(1)

p = -4 + 3

p = -1

Point of intersection (p, j) is (-1, 1).

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