Question

Joel can run around a 1/4 - r mi track in 63 sec , and Jason can run around the track in 57 sec . If the runners start at the same point on the track and run in opposite directions , how long will it take the runners to cover 1/A mi ? Round your answer to the nearest tenth of a second , if necessary .

Answer 1

The  time will it take the runners to cover 1/A mile

t= 5904.6 sec

What time will it take the runners to cover 1/A mile?

Joel takes 63 sec for 14-mile long track

speed of joel

$\frac{14}{1.05} \mathrm{mi} / \mathrm{min}=13.33 \mathrm{mi} / \mathrm{min}$

Jason takes 57 \mathrm{sec} for 14 mi track

so Jason's speed is

$\frac{14}{0.95} \mathrm{mi} / \mathrm{min}=14.74 \mathrm{mi} / \mathrm{min}$

therefore

if both start from the same spot in opposite direction then

$\frac{x}{13.33}=\frac{14-x}{14.74}$

where x is the distance covered by Joel

then$x=131.91 miles$

time required

$t=\frac{131.91}{13.33}=98.41 \mathrm{~min} 5904.6 sec$

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