The perimeter of abc is about 17.21 units.
For given question,
triangle abc with vertices a(-3,3),b(3,-1), and c(-3,-1).
Using distance formula we find the length of the sides ab, bc and ac.
⇒ ab = √[(-1 - 3)² + (3 - (-3))²]
⇒ ab = √(16 + 36)
⇒ ab = √(52)
⇒ ab = 7.21 units
Now, side bc
⇒ bc = √[(-1 - (-1))² + (-3 - 3)²]
⇒ bc = √(0 + 36)
⇒ bc = √(36)
⇒ bc = 6 units
Now we find the length of the side ac.
⇒ ac = √[(-1 - 3)² + (-3 - (-3))²]
⇒ ac = √(16 + 0)
⇒ ac = √(16)
⇒ ac = 4 units
We know that, the perimeter of triangle is the sum of the all sides.
So, perimeter of abc = ab + bc + ac
⇒ P = 7.21 + 6 + 4
⇒ P = 7.21 + 10
⇒ P = 17.21 units
Therefore, the perimeter of abc is about 17.21 units.
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