The perimeter of the polygon is 21 units
How to find the perimeter of the polygon?
The coordinates of the polygon are given as:
A = (0, 4)
B = (2, 0)
C = (2, -2)
D = (0, -2)
E = (-2, 2)
F = (-2, 4)
Calculate the length of each side using
d = √[(x2 - x1)² + (y2 - y1)²]
So, we have:
AB = √[(0 - 2)² + (4 - 0)²] = 4.5
BC = √[(2 - 2)² + (0 + 2)²] = 4
CD = √[(2 - 0)² + (-2 + 2)²] = 4
DE = √[(0 + 2)² + (-2 - 2)²] = 4.5
EF = √[(-2 + 2)² + (2 - 4)²] = 2
FA = √[(-2 - 0)² + (4 - 4)²] = 2
Add the above lengths
Perimeter = 4.5 + 4 + 4 + 4.5 + 2 + 2
Evaluate the sum
Perimeter = 21
Hence, the perimeter of the polygon is 21 units
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