Question

5. An arresting device on a carrier deck stops an airplane in 1.5 s. The average acceleration was
49 m/s². a) What was the stopping distance? b) What was the initial speed?

Answer 1

Answer:

See below

Explanation:

(Using acceleration =  - 49 m/s^2)

vf = vo + at

0 = vo + at

vo = - at

Distance ( or displacement)  =   do + vot + 1/2 at^2  <=====sub in vo = -at

                                               = 0    + -at t  + 1/2 at^2

                                          d = - 1/2 a t^2                                                       since  a = - 49 m/s^2        d = -1/2 ( -49)(1.5^2) = 55.125 m

vf = vo + at

0 = vo + (-49)t = 73.5 m/s   = vo    

( I am not POSITIVE of this answer)