Question

7. A bullet leaves a 28-in rifle barrel at 2700 ft/s. What was a) its acceleration and b) time in the barrel?

Answer 1

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Explanation:

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Answer 2

Answer:

see below

Explanation:

Here are the numbers I find....let me know if they are incorrect:

vf = 2700 f/s

vo = 0

d = 28 in = 2.333 ft

d = 1/2 a t^2

vf = vo + at

vf = at                 <====== sub into the next equation

d = 1/2 a t^2

  = 1/2 vf t

2.333 = 1/2 (2700) t       t = .00173 sec

vf = at

2700 = a ( .00173)     a = 1 562 366  f/s^2