Please help with these 2 problems


The expression can be simplified as follows:
[tex](\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} } = \frac{16}{9}[/tex]
4ˣ⁻¹ = 49 / 4
The expressions can be simplified as follows;
[tex](\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} }[/tex]
Hence,
[tex](\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} } = (\frac{4}{3} )^{2(\frac{2}{3} )}.(\frac{4}{3} ) ^{\frac{5}{3} }[/tex]
Therefore,
[tex](\frac{4}{3} )^{2(\frac{2}{3} )}.(\frac{4}{3} ) ^{\frac{5}{3} } = (\frac{4}{3} )^{\frac{4}{3} } .(\frac{4}{3} )^{\frac{5}{3} }[/tex]
Finally,
[tex](\frac{4}{3} )^{\frac{4}{3} } .(\frac{4}{3} )^{\frac{5}{3} } = (\frac{4}{3} )^{3}[/tex]
[tex](\frac{4}{3} )^{3} = \frac{16}{9}[/tex]
2ˣ = 7
4ˣ⁻¹ = 2²⁽ˣ⁻¹⁾ = 2²ˣ ⁻ ² = 2²ˣ / 2² = (2ˣ)² / 2²
Therefore,
(2ˣ)² / 2² = 7² / 2² = 49 / 4
Hence,
4ˣ⁻¹ = 49 / 4
Finally, the [tex](\frac{16}{9})^{\frac{2}{3} }. (\frac{4}{3} ) ^{\frac{5}{3} }[/tex] is equal to [tex]\frac{16}{9}[/tex] and for the second part 4ˣ⁻¹ = 49 / 4
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