The value of x and y in the given system of equation are 5 and -2 respectively.
Given the equations in the question;
2x + 3y = 4 --------equ i
5x - 2y = 29-------equ ii
Using elimination method, multiply equation i by 2 and equation ii by 3
( 2x + 3y = 4 ) × 2
( 5x - 2y = 29 ) × 3
4x + 6y = 8
15x - 6y = 87
Next, we add the two equation
4x + 6y = 8
15x - 6y = 87
--------------------------------
19x + 0 = 95
Solve for x
19x + 0 = 95
19x = 95
x = 95/19
x = 5
Next, substitute x=5 into equation i and solve for y
2x + 3y = 4
2(5) + 3y = 4
10 + 3y = 4
3y = 4 - 10
3y = -6
y = -6/3
y = -2
Therefore, the value of x and y in the given system of equation are 5 and -2 respectively.
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