The racquet is in contact with the ball for 6.0ms. The average force on the ball during
this time is 400N.
Calculate the impulse on the tennis ball.
The mass of the ball is 0.056 kg.
Calculate the speed with which the ball leaves the racquet.
Find speed

Respuesta :

The impulse of the ball is 2.4 N/s and the speed with which the ball is 42.86 m/s.

The time integral of a force is what is known as its impulse. On the other hand, impulsive forces are strong forces that act on a body quickly. It is described as the speed at which a body's momentum changes when a force is applied.

Impulse = ΔP=Ft= 400×6/100=2.4N/s

An object's change in momentum is known as its impulse.

To calculate this, use the equation p = mv = mv - mu.

You divide the change's rate by the amount of time.

This thus demonstrates the relationship between force and momentum.

The force of the item is equal to the rate of change in momentum, whereΔ p/t = Rate of change in momentum.

Consequently, p/t = m(v-u) / t, which implies that m(v - u) /t= F

Δp /t= F

Now the speed=

ΔP= m(v-u)

v=u+ΔP/m

=0+2.4/0.056

=42.86m/s

To learn more about impulse refer the link:

https://brainly.com/question/904448

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