The kinetic energy at the top of the rock trajectory is 43.57 Joules
The kinetic energy formula and the procedure we will use is:
K.E. = 1/2 m (v*cosθ)²
Where:
Information of the problem:
Applying kinetic energy formula we get:
K.E. = 1/2 m (v*cosθ)²
K.E. = 1/2 * 0.145 kg (32 m/s*cos40°)²
K.E. = 1/2 * 0.145 kg *(24.513 m/s)²
K.E. = 1/2 * 0.145 kg *600.91 m²/s²
K.E. = 87.132 kg m²/s² / 2
K.E. = 43.57 Joules
It is the energy possessed by a body due to its relative motion. It is usually expressed in Joules (J).
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