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Determine the magnitude and direction of the force between two parallel wires 25 m long and 6.0 cm apart, each carrying 25 a in the same direction.

Respuesta :

The magnetic force between two wires is 0.052 N which is  attract each other.

We need to know about magnetic force on a current-carrying wire formula to solve this problem. The magnetic force on two wires with same direction of current is

F = μ₀ . I1 . I2 . L / ( 2π . r )

where μ₀ is vacuum permeability (4π×10‾⁷ H/m) F is the magnetic force, I is current, L is the length of wire, r is distance of 2 wires.

From the question above, we know that:

L = 25 m

r = 6 cm

I1 = I2 = 25 A

By substituting the parameter, we get

F = μ₀ . I1 . I2 . L / ( 2π . r )

F = 4π×10‾⁷ . 25 . 25 . 25 / (2π . 0.06)

F = 0.052 N

Hence, the force between two wires is 0.052 N which is  attract each other.

Find more on magnetic force at: https://brainly.com/question/13277365

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