Question

What is the maximum wavelength, in nm, of light that can eject an electron from a metal with Φ =4.25 x 10–19 J?

Answer 1

The maximum wavelength, in nm, of light that can eject an electron from the metal, given the data is 467.72 nm

Data obtained from the question

From the question given abover, the following data were obtained:

• Energy (E) = 4.25×10¯¹⁹ J
• Wavelength (λ) =?

How to determine the wavelength of the light

• Energy (E) = 4.25×10¯¹⁹ J
• Planck's constant (h) = 6.626×10¯³⁴ Js
• Speed of light (v) = 3×10⁸ m/s
• Wavelength (λ) =?

The wavelength of the light can be obtained as illustrated below:

E = hv / λ

Cross multiply

E × λ = hv

Divide both sides by E

λ = hv / E

λ = (6.626×10¯³⁴ × 3×10⁸) / 4.25×10¯¹⁹

λ = 0.00000046772 m

λ = 467.72 nm

Thus, the wavelength of the light that can eject an electron from the metal is 467.72 nm

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