Question

If sin thita+cosec thita=3,find the value of sin^2thita+cosec^2thita.
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Answer 1

Step-by-step explanation:

sin^2thita+cosec^2thita. = 1,

it have nothing to do with the given values!

Answer 2

Answer:

7

Step-by-step explanation:

using the identities

• (sinΘ + cosecΘ)² = sin²Θ + 2sinΘcosecΘ + cosec²Θ

• cosecΘ = $\frac{1}{sin0}$

then

2sinΘcosecΘ = sinΘ × $\frac{1}{sin0}$ = 1

Hence

sin²Θ + 2sinΘcosecΘ + cosec²Θ = (sinΘ + cosecΘ)² = 3² = 9

sin²Θ + 2 + cosec²Θ = 9 ( subtract 2 from both sides )

sin²Θ + cosec²Θ = 7