Question

h(t) = −t2 + t + 1 h(x + 1)

Answer 1

The value of the function h(x + 1) is -x^2 - x + 1

How to evaluate the function?

The equation of the function is given as:

h(t) =-t^2 + t + 1

The function is given as:

h(x + 1)

This means that t = x + 1

So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1

h(x + 1) =-(x + 1)^2 + (x + 1) + 1

Evaluate the exponent

h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1

Expand the brackets

h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1

Evaluate the like terms

h(x + 1) = -x^2 - x + 1

Hence, the value of the function h(x + 1) is -x^2 - x + 1

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Complete question

Consider the following function definition, and calculate the value of the function

h(t) = −t2 + t + 1 h(x + 1)