Answer:
a. Solve for x. x=16
b. The lenght of the missing side is 10 units.
Step-by-step explanation:
a.
x-6>0 x>6
According to the Pythagorean theorem: a²+b²=c².
Hence,
[tex](x-6)^2+24^2=26^2\\x^2-2*x*6+6^2+24*24=26*26\\x^2-12x+6*6+576=676\\x^2-12x+36+576-676=676-676\\x^2-12x-64=0\\x^2-12x-4x+4x-64=0\\x^2-16x+4x-64=0\\(x*x-16x)+(4x-64)=0\\x*(x-16)+4*(x-16)=0\\(x-16)*(x+4)=0\\x-16=0\\x_1=16\\x+4=0\\x_2=-4\notin\\[/tex]
b.
[tex]16-6=\\10[/tex]
