The value of the given quantity ((-1/4)^3)^-3 by laws of exponent is -262144.
According to the guven question.
We have a quantity [tex]((\frac{-1}{4}) ^{3}) ^{-3}[/tex].
Since, we have to find the value of above quatity by using laws of exponents.
From the laws of exponents we know that
[tex](a^{m}) ^{n} = a^{mn}[/tex]
and [tex]x^{-1} = \frac{1}{x}[/tex]
Therefore, the value of the given quantity is given by
[tex]((\frac{-1}{4}) ^{3}) ^{-3}[/tex]
[tex]= (\frac{-1}{4}) ^{3\times -3}[/tex]
= [tex](\frac{-1}{4}) ^{-9}[/tex]
= [tex]\frac{1}{(\frac{-1}{4} )^{9} } }[/tex]
= (-4)^9
= -262144
Hence, the value of the given quantity ((-1/4)^3)^-3 by laws of exponent is -262144.
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