Question

PLS HELP

The coordinates of the midpoint of segment GH are M(−132,−6) and the coordinates of one endpoint are G(−4, 1).

Answer 1

The coordinates of the H are H(-260,-11).

According to the statement

we have given that the mid point value GH are (−132,−6) and the coordinates of one endpoint are G(−4, 1). and we have to find that the coordinates of H.

So, For this purpose, we know that the

Midpoint formula is a mathematical equation that is used to locate the halfway point between two data points.

So, The given points are:

GH(−132,−6) and the G(−4, 1).

The midpoint of the GH are

$GH = (\frac{x_{1} +x_{2}}{2} , \frac{y_{1} + y_{2} }{2} )$

Substitute the values in it then

$(-132,-6) = (\frac{-4 +x_{2}}{2} , \frac{1 + y_{2} }{2} )$

now compare it then

-4+x/2 = -132 and 1+y/2 = -6

x -4 = -264 and 1+y = -12

x = -260 and y = -11.

So, The coordinates of the H are H(-260,-11).

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