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The fuel used in many disposable lighters is liquid butane, C4H10 . Butane has a molecular weight of 58.1 grams in one mole. How many carbon atoms are in 1.00 g of butane?

Respuesta :

1.6586 x 10 atoms are in 1.00 g of butane.

Avogadro's constant is 6.0221023, a value that is constant for all particles. Calculate the number of moles that 4 g of butane represents, then multiply that number by Avogadro's constant to obtain the number of particles.

So how many moles are needed to equal 4g if 1 mole is equal to 58.1g?

We divide by 58.1 and cross multiply (4x1).

= 0.068847 moles

Avogadro constant multiplied by 4.1466 x 10 molecules

But keep in mind that the question concerns the number of carbon atoms, not the number of butane molecules.

Since butane comprises four carbon atoms with a total of 4.1466 x 1022 atoms,

We multiply the result by four to find the number of atoms.

similar to 1.6586 x 10 atoms

1.6586 x 10 atoms are in 1.00 g of butane.

Learn more about here a number of atoms brainly.com/question/2702826

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