The comparison for the given irrational numbers, √131 and √111.8 is √131 > √111.8.
A rational number is any number, that can be represented in the form of p/q, where p and q are integers, q ≠ 0, and p and q are co-prime numbers.
Any number which cannot be represented in the discussed way is irrational.
In the question, we are given two irrational numbers, √131 and √111.8, and are asked to compare them.
The value of the given irrational number, √131 = 11.4455231423...
The value of the given irrational number, √111.8 = 10.5735519103...
Now, we know that 11.4455231423... > 10.5735519103..., which implies that:
√131 > √111.8.
Thus, the comparison for the given irrational numbers, √131 and √111.8 is √131 > √111.8.
Learn more about irrational numbers at
https://brainly.com/question/11919233
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