Respuesta :

Answer:

x=2 and x=-2

Step-by-step explanation:

Original Equation:

[tex]x^2-6x=-6x+4\\[/tex]

Add 6x to both sides

[tex]x^2=4[/tex]

Subtract 4 from both sides

[tex]x^2-4=0[/tex]

Use difference of squares: [tex]a^2-b^2=(a-b)(a+b)[/tex]

[tex](x-2)(x+2)=0[/tex]

Since the factors are being multiplied by each other, if one of the factors is equal to zero, then the entire thing becomes zero, since 0 * anything = 0

So to find the values of x that satisfy this equation, set each factor equal to zero

[tex]x-2=0[/tex]

Add 2 to both sides

[tex]x=2[/tex]

[tex]x+2=0[/tex]

subtract 2 from both sides

[tex]x=-2[/tex]

We have both values that satisfy this equation, x=2 and x=-2

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