The option [tex]1.50+0.50x\leq 25;x\leq 47\\[/tex] is the correct option.
A flat fee of $1.50 is charged by the taxicab with an additional $0.50 for each mile.
If she has $25 to spend, the miles travelled will be:
[tex]1.50+0.50(x-1)\leq 25[/tex]
[tex]1.50 + 0.50x - 0.50 < 25[/tex]
Solving further,
[tex]0.50x < 24[/tex]
Therefore,
[tex]x < 48[/tex]
Thus, miles less than and equal to 47 can be travelled.
[tex]1.50+0.50x\leq 25;x\leq 47\\[/tex] is the answer.
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