Question

PLEASE HELPPPPPP ASAPPPP!!!!!!!!

Find the sum of the first 15 terms for the geometric sequence

12, 4, 4/3, ......

Answer 1

Answer:

$\frac{28697812}{1594323}$

Step-by-step explanation:

$\frac{12(1-(1/3)^{15})}{1-(1/3)} =\frac{28697812}{1594323}$