Question

hurry PLSSS HELP I WILL GIVE 33 or more points plssssshelp
Two friends are planning for a gathering. The food budget is modeled by one half times the absolute value of the quantity x minus 120 end quantity equals 10 comma where x is the amount spent on food. What are the least and greatest amounts that the two friends could spend on food?

$50, $70
$100, $140
$110, $130
$115, $125

Answer 1

Answer:

$100, $140

Explanation:

$\sf \rightarrow \dfrac{1}{2} |x-120| = 10$

$\sf \rightarrow |x-120| = 2(10)$

$\sf \rightarrow |x-120| = 20$

$\sf \rightarrow x-120 = \pm 20$

$\sf \rightarrow x-120 = 20 \quad or \quad x - 120 = -20$

$\sf \rightarrow x= 20+120 \quad or \quad x = -20+120$

$\sf \rightarrow x= 140\quad or \quad x = 100$

Hence, the least amount is $100 and greatest amount is $140.

Answer 2

Answer:

100, 140

Step-by-step explanation: