The distance between the first- and second-order dark fringes on the screen is 487.4 nm
For given question,
We have been given monochromatic light with wavelength 590 nm passes through a single slit 2.30 m wide and 1.90 m from a screen.
So λ = 590 nm
d = 2.30 m
D = 1.90 m
We need to find the distance between the first- and second-order dark fringes on the screen.
We know that the distance between two consecutive dark fringes or bright fringes on the screen is,
β = λD / d
Substituting the values,
⇒ β = (590 × 10^(-9) × 1.90) m/ 2.30 m
⇒ β = 1121 × 10^(-9) / 2.30
⇒ β = 487.4 × 10^(-9)
⇒ β = 487.4 nm
Therefore, the distance between the first- and second-order dark fringes on the screen is 487.4 nm
Learn more about the dark fringes here:
https://brainly.com/question/8896900
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